Question

If A = 2tan^-1(2√2 - 1) and = 3sin^-1(1/3) + sin^-1(3/5), then prove that A > B

Answer 1

Given,

A = 2tan^-1(2√2 - 1)

⇒ B < π/3 + π/3 = 2π/3

Hence, A > B