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Let [cot(∑cot^-1(k^2 + k + 1) for k ∈ [k =1, 10])] = a/b

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asked Nov 11, 2019 in Sets, relations and functions by SumanMandal (54.6k points)

Let [cot(∑cot^-1(k² + k + 1) for k ∈ [k =1, 10])] = a/b

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1 Answer

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answered Nov 11, 2019 by Raghab (50.3k points)
selected Nov 11, 2019 by SumanMandal

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Hence, the value of(a + b + 10) is 21.

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