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If tan-1y = 4tan-1x, (|x| < tan(π/8)), find y as an algebraic function of x and hence prove that tan(π/8) is a root of the equation x4 - 6x2 + 1 = 0

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Given tan-1y = 4tan-1x

Hence, x4 - 6x2 + 1 = 0

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