Question

If a, b and g are the three zeroes of the polynomial p(x) = x³ – 64x – 14, what is the value of α³ + β³ + γ³ ? 

(1) 36 

(2) 40 

(3) 42 

(4) 64

Answer 1

Correct option (3) 42

Explanation:

P (x) = x³ – 64x – 14

α + β + γ = 0, αβ + βγ + γα = – 64, αβγ = 14 

α³ + β³ + g³ = 3αβg = 42