Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
19.9k views
in Mathematics by (64.8k points)

What is the remainder when the polynomial p(x) = x200 – 2x199 + x50 – 2x49 + x2 + x + 1 is divided by (x – 1) (x – 2) ? 

(1) 1 

(2) 7 

(3) 2x + 1 

(4) 6x – 5 

1 Answer

+1 vote
by (58.4k points)
selected by
 
Best answer

Correct option (4) 6x – 5

Explanation:

f(x) = x200 – 2x199 + x50 –2x49 + x2 + x + 1 

f(x) = (x – 1)(x – 2) q(x) + ax + b

1 – 2 + 1 – 2 + 1 + 1 + 1 = a + b

1 = a + b

2200 – 2200 + 25 – 250 + 4 + 2 + 1 = 2a + b 

7 = 2a + b

– 6 = – a  a = 6

∴ b = –5

∴ 6b = –5

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...