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If the solution set of sin-1(sin((2x2 + 4)/(x2 + 1)) < π - 3 is (a, b), where a, b ∈ I, then find (b - a + 5)

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Given, sin-1(sin((2x2 + 4)/(x2 + 1)) < π - 3

Hence, the value of (b - a + 5) = 1 + 1 + 5 = 7.

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