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in Sets, relations and functions by (50.2k points)

If 0 < x < 1, then √(1 + x2) x [{xcos(cot-1x) + sin(cot-1x)]1/2 equals

(a) x/√(1 + x2)

(b) x

(c) x√(1 + x2)

(d) √(1 + x2)

1 Answer

+1 vote
by (54.5k points)
selected by
 
Best answer

Correct option (c) x√(1 + x2)

Explanation:

(1 + x2) x [{xcos(cot-1x) + sin(cot-1x)]1/2

(1 + x2) x [{xcos(cot-1x) + sin(cot-1x)]1/2

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