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If cos(sin-1√(1 - x2)) = sin(tan-1(x√6)), x ≠ 0 then the value of x is ...

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Given, cos(sin-1√(1 - x2)) = sin(tan-1(x√6))

cos(sin-1√(1 - x2)) = sin(tan-1(x√6))

⇒ 6(1 - x2) = (6x2 + 1)

⇒ 6 - 6x2 = 6x2 + 1

⇒ 12x2 = 5

⇒ x2 = 5/12

⇒ x = ±√(12/5)

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