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in Integrals calculus by (38.6k points)

Evaluate: ∫ (sec x (2 + sec x)/ (1 + 2sec x)2) dx

1 Answer

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Best answer

The given integral is

∫ (sec x (2 + sec x)/ (1 + 2sec x)2) dx 

= ∫ (2cos x + 1/ (cos x + 2)2) dx

= ∫ ((cos x (cos x + 2) + sin x)/ (cos x + 2)2) dx

= ∫ (cos x/ cos x + 2) dx + ∫ (sin x (cos x + 2)2) dx

= (1/ cos x + 2) ∫ cos dx – ∫ (sin x/ (cos x + 2)2) dx + ∫ (sin x/ (cos x + 2)2) dx  + c 

= (sin x/ cos x + 2) + c

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