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in Integrals calculus by (36.9k points)

Evaluate: ∫ ex (2sec2 x – 1)tan x dx

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∫ ex (2sec2 x – 1)tan x dx 

= ∫ ex (2 sec2 x tan x – tan x) dx 

= ∫ ex [(sec2 x – tan x) + (2sec2 x tan x – sec2 x)] dx 

= ∫ ex (sec2 x – tan x) + c

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