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+1 vote
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in Integrals calculus by (36.9k points)

Evaluate: ∫ ex (log x + (1/x2)) dx

1 Answer

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Best answer

∫ ex (log x + (1/x2)) dx 

= ∫ ex {(log x – (1/x)) + ((1/x) + (1/x2))} dx 

= ex (log x – (1/x)) + c

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