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in Limit, continuity and differentiability by (54.6k points)

Let f(x) = {((sinx + cosx)cosecx, : - 1/2 ≤ x < 0), (a, : x = 0), ((e1/x + e2/x + e3/|x|)/(ae2/x + be3/|x|), : 0 < x ≤ 1/2) If f(x) is continuous at x = 0, find the value of {e(a + b) + 2}.

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Best answer

We have lim(x→0)  (sinx + cosx)cosec x 

= lim (x→0)  (1 + (sinx + cosx – 1))cosec x

= elim (x→0) (sinx + cosx – 1)/sinx

Since f(x) is continuous at x = 0, so

lim (x→0+)  f(x)  = lim (x→0) f(x) = f(0)

1/b = e = a

Thus, a = e, b = 1/e

Hence, the value of {e(a + b) + 2}

= {e( e + 1/e ) + 2}

= (e2 + 3)

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