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in Integrals calculus by (36.9k points)

Evaluate: ∫ sec3 x dx

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Best answer

Let I = ∫ sec3 x dx 

= ∫ (sec2 x .sec x) dx 

= sec x ∫ sec2 x dx – ∫ (sec x .tan x .tan x) dx 

= sec x ∫ sec2 x dx – ∫ (sec x .tan2 x) dx 

= sec x. tan x – ∫ (sec x (sec2 x – 1)) dx 

= sec x. tan x – ∫ sec3 x dx + ∫ sec x dx 

2I = sec x .tan x + ∫ sec x dx 

2I = sec x .tan x – log |sec x + tan x| + c 

I = (1/2) (sec x .tan x + log |sec x + tan x|) + c

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