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in Integrals calculus by (36.9k points)

Evaluate: ∫ cosec3 x dx

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Let I = ∫ cosec3 x dx 

= ∫ cosec3 x .cosec x dx 

= cosec x ∫ cosec2 x dx – ∫ (– cosec x .cot x. – cot x) dx 

= – cosec x .cot x – ∫ cosec x .cot2 x dx 

= – cosec x .cot x – ∫ cosec x (cosec2 x – 1) dx 

= – cosec x .cot x – ∫ cosec3 x dx + ∫ cosec x dx 

2I = – cosec x .cot x + ∫ cosec x dx 

2I = – cosec x .cot x + log |cosec x – cot x| + c

I = (1/2) (– cosec x .cot x + log |cosec x – cot x| + c

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