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in Chemical thermodynamics by (64.8k points)

Match the column I with column II:

Column I (Ideal Gas) Column II (Related equations)
(A) Reversible isothermal process (p) W=2.303 nRT log (P2 /P1 )
(B) Reversible adiabatic process (w) W=nCVm (T2 -T1 )
(C) Irreversible adiabatic process (r) W=-2.303nRT log (V2 /V1)
(D) Irreversible isothermal process

1 Answer

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Best answer

Correct option Ap, r, s; Bq, s; Cq, s; Ds

Explanation:

(i) Reversible isothermal 

P = –nRT ln V2/V1 = 2.303 nRT log P2/p1

(p, r)

(ii) Reversible adiabatic = w = ∆U = nCV (T2 – T1) qs

(iii) Irreversible adiabatic = nCV ∆T = –Pex dV

(iv) Irreversible isothermal w = – ∫Pex dV

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