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in Integrals calculus by (36.9k points)

Evaluate: ∫ 3√tan x dx

1 Answer

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Best answer

Let tan x = t3 

sec2 x dx = 3t2 dt

dx = (3t2 / sec2 x) dt 

= (3t2 / 1 + t2) dt

Let t2 = v

2t dt = dx

where v = t2 = (tan x)2/3

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