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+1 vote
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in Chemical thermodynamics by (64.8k points)

One mole of an ideal gas at 300 K in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm. In this process, the change in entropy of surroundings (∆Ssurr) in JK-1 is (1 L atm = 101.3 J)

(A) 5.763 

(B) 1.013 

(C) -1.013 

(D) -5.763

1 Answer

+2 votes
by (58.4k points)
selected by
 
Best answer

Correct option (C) -1.013

Explanation:

∆= + Eqw

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