Question

The population of a town increase by 10% annually. If the present population is 22000, find it population a year ago.

Answer 1

Present population of town = 22000

Rate of increase in population annually = 10%

Let the population 1 year ago be x .

Now,

(x + 10% of x) = 22000

(x + x/10) = 22000

11x/10 = 22000

x = 22000 x 10/11

x = 20000

So,

The population 1 year ago will be 20000.