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in Integrals calculus by (36.9k points)
edited by

Evaluate : ∫ (√(1 + x8)/x13) dx 

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1 Answer

+1 vote
by (38.6k points)

= ∫ {x–13(1 + x8)1/2}dx

Here,

Let (1 + x8) = x8 t2 

x8 = 1/(t2 – 1) 

8x7 dx = – 2t/(t2 – 1) dt 

4x7 dx = – t/(t2 – 1) dt

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