Let x = −1/3
S = (1 + x)(1 + x2 )(1 + x4 )….
(1 − x)S = (1 − x)(1 + x)(1 + x2 )(1 + x4 )…
(1 − x)S = (1 − x2)(1 + x2)(1 + x4)(1 + x8 )…..
(1 − x)S = (1 − x4)(1 + x4 )(1 + x8)…..
Since x < 0 & |x| < 1 so the value of RHS would be equals to 1.
(1 − x) S = 1 or S = 1/(1 − x) or 1/(1 −(−1/3)) =3/4.