Isolate the box. The weight vector is
W2 = (22)(9.81)j = -215.8j (N).
The angle between the normal force and the positive x axis is (90° - 60°) = 30°.
The normal force is NB = |NB|(0.866i - 0.5j).
The angle between the rope CD and the positive x axis is (180° - 75° = 105°); the tension is:
Isolate the friend. The weight is
W = -(90)(9.81) = -882.9j (N).
The angle between the normal force and the positive x axis is (90° - 40°) = 50°. The normal force is:
NF = |NF|(0.6428i + 0.7660j).
The angle between the lower rope and the x axis is -75°; the tension is
T2 = |T2|(0.2588i + 0.9659j)
The angle between the tension in the upper rope and the positive x axis is (180° - 20° )= 160°, the tension is
T1 = |T1|(0.9397i + 0.3420j).
The equilibrium conditions are