To check for invertibility of f(x):
(i) For one-to-one function: Let x1x2 ∈ R and x1 < x2. Then
ex < ex2 (As e > 1) ....(1)
Also,
x1 < x2 ⇒ −x2 < −xz
⇒ e-x2 < e-x1 .......(2)
On adding Eqs. (1) and (2), we get
where f is an increasing function. Hence, f(x) is a one-to-one function.
(ii) For onto function: Since x → ∞, f(x) → ∞. Similarly, at x → −∞, f(x) → −∞. That is,
−∞ < f(x) < ∞, x ∈ (−∞, ∞)
Hence, the range of f is the same as the set R. Therefore, f(x) is an onto function. Since f(x) is both one-one and onto functions, f(x) is invertible.
(iii) To find f −1: We have