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If A = 1/π [(sin^-1 (πx), tan^-1(x/π),(sin^-1(x/π), cos^-1, (πx))], B = 1/π [(-cos^-1 (πx) tan^-1 (x/π),(sin^-1 (x/π, -tan^-1 (πx))]

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If A = 1/π [(sin-1 (πx), tan-1(x/π),(sin-1(x/π), cos-1, (πx))], B = 1/π [(-cos-1 (πx) tan-1 (x/π),(sin-1 (x/π, -tan-1 (πx))] the A -B is equal to 

(1) 0

(2) 1I/2

(3) I

(4) 2I

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Correct option (2) 1I/2

Explanation:

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