# Let f : R → R be defined by f(x) = 2x + 6 which is bijective mapping then f^-1 (x) is given by

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Let f : R → R be defined by f(x) = 2x + 6 which is bijective mapping then f-1 (x) is given by

(1) 2x + 6

(2) 6x + 2

(3) x-3/2

(4) x -3

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Correct option (3) x -3/2

Explanation: