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The principal value of sin^-1(sin10) is (A) 10 (B) 10 - 3π

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in Trigonometry by (41.6k points)

The principal value of sin-1(sin10) is

(A) 10

(B) 10 - 3π

(C) 3π - 10

(D) None of these 

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1 Answer

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Best answer

Correct option (C) 3π - 10

Explanation:

Since

3π < 10 < 7π/2

⇒ - π/2 < 3π - 10 < 0

Now,

sin-1(sin10) = sin-1[sin(3π - 10)]

= 3π - 10

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