Correct option (c) {π}
Explanation :
We have
Since x2 + 1/2 ≥ 1/2, we get
x2 + 1/2 ≥ 1/2, we get
[x2 + 1/2] = 0 or 1
Since sin−1 [x2 + (1/2)] is defined only for these two values,
(i) when [ (x2 + (1/2)] = 0, we get
f(x) = sin−10 + cos−1(−1) = (ii) when [ ( x / )] 2 + 1 2 = 1, we get f(x) = sin−11 + cos−10 =
(ii) when [x2 + (1/2)] = 1, we get
f(x) = sin−11 + cos−10 = π
Therefore, the range of f(x) = {π}.