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+1 vote
8.4k views
in Sets, relations and functions by (53.3k points)

If f(x) is a function that is odd and even simultaneously, then f(3) − f(2) is equal to

(A)  1

(B)  −1

(C)  0

(D)  None of these 

1 Answer

0 votes
by (53.4k points)
selected by
 
Best answer

Correct option  (C) 0 

Explanation :

We have

f(x) = 0 ∀x ∈ R ⇒ f(3) − f(2) = 0

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