Question

sin^-1(2x√(1 - x²)) for -1 ≤ x ≤ 1 is equal to

(A) π - 2sin^-1(x) 1/√2 ≤ x ≤ 1

(B) 2sin^-1(x) for - 1/√2 ≤ x ≤ 1/√2

(C) - π - 2sin^-1(x) for - 1≤ x ≤ - 1/√2

(D) 2cos^-1(x) for 1/√2 ≥ x ≤ 1

Answer 1

Correct option (A), (B), (C)

Explanation: