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The value of 2cot (cot-13 + cot-17 + cot-113 + cot-121) is _________.

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Best answer

cot[tan-1(1/3) + tan-1(1/7) + tan-1(1/13) + tan-1(1/21)]

Using, tan-1x + tan-1y = tan-1[(x + y)/(1 - xy)], we get

cot[tan-1(1/2) + tan-1(1/8)] = 3/2

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