Question

The number of solutions of log_sinx 2 ^{tan x} > 0 in the interval (0,π/2) is

(A)  0

(B)  1

(C)  2 

(D)  3

Answer 1

Correct option   (A) 0

Explanation :

Let

For f (x) > 0, we must have tan x > 0 and In sin x > 0 Now, 

and 0 < sin x < 

 ⇒ < lnsin x 0 (As ln x < 0, for 0 < x <1)

Therefore, there is no solution for f (x) > 0.