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in Sets, relations and functions by (53.3k points)

Let P  = {(x,y) |x2 + y2 = 1,x,y ∈ R}. Then P is

(A)  Reflexive

(B)  Symmetric

(C)  Transitive

(D)  Anti-symmetric

1 Answer

+1 vote
by (53.1k points)
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Best answer

Correct option  (B) Symmetric 

Explanation :

Obviously, the relation is not reflexive and transitive, but it is symmetric because x2 + y2 = 1 ⇒ y2 + x2 = 1

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