Question

If f(x) = |(x, cosx, e^x2), (sinx, x², secx), (tanx, 1, 2)|,  then the value of ∫f(x)dx for x ∈ [-π/2, π/2] is equal to

(A) 0

(B) 1

(C) 2

(D) None of these

Answer 1

Answer is (A) 0

f(-x) = -f(x). It is an odd function. Hence,