Answer is (B) A skew-symmetric matrix if it exists
If A is a skew-symmetric matrix of odd order, then |A| = 0.
So, inverse does not exist.
Let A be of even order. Then
AA-1 = A-1A = In ⇒ (AA-1)T = (A-1A)T = In
⇒ (A-1)T AT = AT(A-1)T = In
⇒ (A-1)T (-A) = (-A)(A-1)T = In
So, (A-1)T = -A-1 (inverse of a matrix is unique).