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in Physics by (50.3k points)

A particle of mass m is fixed to one end of a light spring of force constant k and unstretched length l. The system is rotated about the other end of the spring with an angular velocity ω, in gravity free space. The increase in length of the spring will be

(a) mω2l / k

(b) mω2l / k - mω2

(c) mω2l / k + ω2

(d) none of these

1 Answer

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Best answer

Correct Answer is: (b) mω2l / k - mω2

Let x = the increase in the length of spring. Then the particle moves along a circular path of radius (l + x), and the spring force = kx = centripetal force.

∴ mω( l + x ) = kx  or  x = mω2l / k-mω2.

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