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in Trigonometry by (41.4k points)

Let x1y1z1, x2y2z2 and x3y3z3 be three 3-digit even numbers and Δ = |(x1, y1, z1), (x2, y2, z2), (x3, y3, z3)|. Then, Δ is

(A) Divisible by 2 but not necessarily by 4

(B) Divisible by 4 but not necessarily by 8

(C) Divisible by 8

(D) None of these 

1 Answer

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Best answer

Answer is (A) Divisible by 2 but not necessarily by 4

which is divisible by 2 but not necessarily by 4 or 8.

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