If p, q, r are in AP, then the determinant |(a^2 + 2^n + 1 + 2p, b^2 + 2^n + 2 + 3q, c^2 + p), (2^n + p, 2^n + 1 + q, 2q),

If p, q, r are in AP, then the determinant |(a² + 2^{n + 1} + 2p, b² + 2^{n + 2} + 3q, c² + p), (2ⁿ + p, 2^{n + 1} + q, 2q), (a² + 2ⁿ + p, b²+ 2^{n + 1} + 2q, c² - r)| is equal to

(A) 1

(B) 0

(D) (a² + b² + c²) - 2ⁿq

If p, q, r are in AP, then the determinant |(a^2 + 2^n + 1 + 2p, b^2 + 2^n + 2 + 3q, c^2 + p), (2^n + p, 2^n + 1 + q, 2q),

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