(A) Let |A| = |aij| 3 × 3 ≠ 0. Each element aij is multiplied by k^i - j.

Question

Match the following:

Column I	Column II
(A) Let |A| = |aij| 3 × 3 ≠ 0. Each element aij is multiplied by ki - j. Let |B| the resulting determinant, where k1|A| + k2|B| = 0. Then k1 + k2 =	(p) 0
(B) The maximum value of a third-order determinant each of its entries are ±1 equals	(q) 4
	(r) 1
where A and B are determinants of order 3. Then A + 2B =	(s) 2
	(t) |(1, 2), (2, 4)|

Answer 1

Answer is (A) → (p, t), (B) → (q), (C) → (r), (D) → (p, t)