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Prove the identity: (cosA + cosB) (cos2A + cos2B) (cos2^2 A + cos2^2 B) … (cos2^n−1A + cos2^n-1 B) = (cos2^n A - cos 2^n B)/2^n (cosA - cosB).

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Prove the identity:

(cosA + cosB) (cos2A + cos2B) (cos22A + cos22B) … (cos2n−1A + cos2n-1B) =  (cos2nA - cos 2n B)/2n(cosA - cosB).

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Proceeding in this manner, we get

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