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in Physics by (50.3k points)

A ring of mass m rolls down an inclined plane with acceleration a without slipping. The plane makes an angle θ with the horizontal. The force of friction acting on the ring is equal to 

(a) ma 

(b) mg sin θ 

(c) m(gsin θ - a) 

(d) the limiting friction

1 Answer

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by (51.1k points)
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Best answer

Correct Answer is: (a) ma

τ = Fr = Iα = (mr2)(a/r)

∴ F= ma.

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