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A solid sphere of radius r rolls without slipping on the floor, with linear momentum p.

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A solid sphere of radius r rolls without slipping on the floor, with linear momentum p. Its angular momentum with respect to a point on the floor is 

(a) 2pr/5 

(b) 3pr/5 

(c) 3pr/7 

(d) 7pr/5

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Correct Answer is: (d) 7pr/5

Angular momentum with respect to a point on the floor

= angular momentum about C + pr

= Iω + pr = (2/5 mr2) (v/r) + mvr = 7/5 pr.

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