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in Trigonometry by (53.1k points)
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Find the most general value of θ satisfying the equation tanθ = -1 and cos θ = 1/√2.

1 Answer

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Best answer

tan θ = - 1 = tan(2π - π/4)

and cosθ = 1/√2 = cos(2π - π/4)

Hence, the general value is

θ = 2nπ + (2π - π/4) = 2nπ + 7π/4

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