Replacing cos2x by 1 − sin2x, we get a quadratic in sin of the form
4sin2x + 4sinx −3 = 0
⇒ (2sinx + 3) (2sinx −1) = 0
Now
sin x ≠ − 3/2 since |sin x| ≤ 1
Therefore, sin x = 1/2
The principal solution is x = π/6.
The general solution is x = nπ +(-1)nπ/6.