Question

Let f be a function defined on the set of the real numbers such that for x ≥ 0, f(x) = 3sin x + 4cos x. Then f(x) at x = -11π/6 is  equal  to

(A)   3/2 + 2√3

(B)   -3/2 + 2√3

(C)  3/2 - 2√3

(D)  -3/2 - 2√3

Answer 1

 Correct  option (B)  -3/2 + 2√3