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in Trigonometry by (53.3k points)

If A > 0, B > 0 and A + B = π/6 then the minimum value of tanA + tanB is

(A)   √3 - √2

(B)   4 - 2√3

(C)   2/√3

(D)   2 - √3

1 Answer

+1 vote
by (53.5k points)
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Best answer

Correct option (B)  (B)  4 - 2√3

We have A > 0, B > 0 and A + B = π/6. Therefore,

For the maximum value of tan A + tan B, A = B. Therefore, from the above equation, we get

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