Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.2k views
in Trigonometry by (53.3k points)

The number of solutions of sin3x cos x + sin2x cos2x + sin x cos3x = 1 in [0, 2π] is

(A)  4 

(B)  2 

(C)  1 

(D)  0

1 Answer

+1 vote
by (53.4k points)
selected by
 
Best answer

Correct option  (D) 0

sinx cos x [sin2x + sin x cos x + cos2x] = 1

which is not possible.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...