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in Trigonometry by (53.3k points)

The equation sin4x - 2cos2x + a2 = 0 The equation if

(A)  -√3 ≤ a ≤ √3

(B)  -√2 ≤ a ≤ √2

(C)  −1 ≤ a ≤ 1

(D)  None of these

1 Answer

+1 vote
by (53.4k points)
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Best answer

Correct option (B)  -√2 ≤ a ≤ √2 

We have sin4 x - 2cos2 x + a2 = 0. Let y = sin2 x. Then

For y to be real, Discriminant ≥ 0.

So  4 - 4(a2 - 2)≥0 ⇒ a2 ≤ 3   .....(1)

But  sin2 x = y. Therefore 0 ≤1 ≤ y . So

From Eqs. (1) and (2), a2 ≤ 2

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