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One solution of the equation 4cos^2 θsinθ - 2sin^2θ = 3 sinθ is

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One solution of the equation 4cos2 θsinθ - 2sin2θ = 3 sinθ is

(a)  θ = nπ + (-1)n(-3π/10)

(b)  θ = nπ + (-1)n(-3π/10)

(c)  θ = 2nπ ± π/6

(D)  None of these 

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1 Answer

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Best answer

Correct option (a)  θ = nπ + (-1)n(-3π/10)

The given equation can be written as

Therefore, either sin θ = 0 which gives θ = nπ

Thus, one solution of the given equation is

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