Question

If y√(x² + 1) = log(√(x² + 1) - x), then (x² + 1)dy/dx + xy + 1 is equal to

(A) 0 

(B) 1 

(C) 2 

(D) None of these 

Answer 1

Answer is (A) 0

y√(x² + 1) = log[√(x² + 1) - x]

Differentiating both sides with respect to x, we get

Comments

Very good answer.