Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
665 views
in Physics by (50.3k points)

Let ν1 be the frequency of the series limit of the Lyman series, ν2 be the frequency of the first line of the Lyman series, and ν3 be the frequency of the series limit of the Balmer series. 

(a) ν1 - ν2 = ν3 

(b) ν2 - ν1 = ν3 

(c) ν3 = 1/2 (ν1 + ν2

(d) ν1 + ν2 = ν3

1 Answer

+1 vote
by (51.1k points)
selected by
 
Best answer

Correct Answer is: (a) ν1 - ν2 = ν3 

Series limit means the shortest possible wavelength (maximum photon energy), and first line means the longest possible wavelength (minimum photon energy) in the series.

ν = c [1/n2 - 1/m2], where c = constant.

For series limit of the Lyman series, n = 1, m = , ν1 = c.

For first line of the Lyman series, n = 1, m = 2, ν2 = 3c/4 .

For series limit of the Balmer series, n = 2, m  , ν3 = c/4.

 ∴ ν1 - ν2 = ν3.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...