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in Limit, continuity and differentiability by (41.4k points)

A wire of length 2 units is cut into two parts which are bent respectively to form a square of side x units and a circle of radius r units. If the sum of the areas of the square and the circle so formed is minimum, then

(A) 2x = r

(B) 2x = (π + 4)r

(C) (4 − π)x = πr

(D) x = 2r

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Answer is (D) x = 2r

Side length of the square = x

Radius of circle = r

Perimeter of square + Perimeter of circle = 2

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